WEEK 16 PHYS 31 CE ASYNCH

0:25 Okay good morning Good day everyone I will be having my recorded lesson which is all about capacitance and capacitors Okay so any idea about these terms So if you want to differentiate the two when we say capacitors Uh these are being referred to the device so capacitors is a device while capacitance is the amount Okay so the amount that can be found on the capacitor is the capacitance Okay so let's define

1:13 it so capacitance is the ratio of charge gained per potential gained of conductors So this is being referred to the ratio of q and v so the unit of the capacity is colum per volt or commonly known as farad Okay so based from the definition of capacitance which is ratio of charge gained per potential gained of conductors we have now the formula c is equ to Q / B so again C or capacitance is equal to

2:00 um charge gained over potential gain and then the unit of course is farad or colum per volt Okay so capacitance Class is considered as a scalar quantity okay now there is a graph here shown below wherein it signifies the relationship between the charge gain and the potential gain of conductor So what does this graph means okay so kung titingnan natin mabuti This is the point of origin Uh for with the coordinates of zer and zer followed by q and then um Q is for

2:49 y-axis and then V is for x-axis and then if you have noticed from Q it increases to ah 2 Q so when the charge increases to 2q the volt or the potential gain also increases to two Okay So ibig sabihin when Q is doubled the volt is also double Okay so or the potential gain is also double when Q is tripled V is also triple So ibig

3:37 sabihin charge gain is directly proportional to the potential gain so when the charge increases the potential also increases we can increases the charge also increases Okay so the relationship is directly proportional with each other okay now kung mag-draw tayo ng or magra tayo and then we're going to connect the points we can form a straight line kasi nga ba directly

4:23 proportional so we have a straight line here now from the x-axis of course to the line that we have form based on the coordinates of Uh q and B there is now an angle TH Okay so there is an angle TH here now in order to get the capacitance based on the angle theta then we can use this [Musika] formula now there is a linear relationship between gain and gain charge and gain potential Okay so we all know know that the relationship is directly proportional or linear so slope of the

5:08 graph gives us the capacitance of The Force kasi kung ni-recall ninyo sa algebra agag meron tayong line um let's say na pakanan Ibig sabihin meron siyang slope kung pakaliwa may slope din pero kung pakanan ang slope natin sa algebra is positive now kung ang line natin sa sa coord sa cartesian plane ay paft ang slope natin is negative tapos pag ang line natin ay horizontal so zero agag vertical undefined Pero in this case since ang mfo natin na graph or [Musika] ma-off natin ay straight line or yung

5:54 linear ibig sabihin meron tayong angle of inclination or angle of elevation Okay pataas yung angle okay at nasa first quadrant kaya positive yun So yung tangent theta natin is equal to Q / V so since ang Q / V natin is equal to C So ibig sabihin ang tangent theta is also equal to the capacitance so Bakit naging equal sa q and v yung tangent So kung titingnan natin ulit ' ba itong line na to nasa y- axis natin is Q which is the opposite of the angle and then itong savs is the adjacent of the angle Ano ba definition ng tangent toa So ibig

6:41 sabihin opposite side divided by the adjacent side kaya based from this figure na formulate Iyung tangent theta is equal to the opposite side which is q and then the adjacent side which is V Okay so again tangent theta natin is equal to Q / B we in based from Our first statement of the definition of capacitance ang Q / B is equ to C or the capacitance Okay so take note of that meron na tayo ngayong dalawang formula for ah C so yyung Q / B now kung given naman yung angle then we can use tangent theta is equal to the

7:28 capacitance okay now since naka-indicate na ang unit ng capacitance is column per volt or farad Ah pero yyung commonly used daw is PF which means peak of farad which is equivalent to 10 - 12f So yung p ko dito is ah just a prefix similar with micr columb ung na-mention ko before ng micro so or pwede ring nano or pwede ring ah kilo ' ba Okay so again for capacitance sa commonly known Uh or the commonly used unit is PF denotes

8:13 picofarad which is equivalent to 10 rais -1 farad or you can use also microfarad which is muf equivalent to 10 ra -6 farad and then nf or known as nanofarad which is 10 ra -9 farad okay now if the sphere or The conductor sphere with a radius and a charge has as a capacitance also wherein ah based from our lesson Before yung V natin or the potential G is equ to k * Q / R at and

8:59 then So kung ide derive natin Iyung formula then we have now c equ r / q So if ever na given yung yung radius At saka nung ah charge then we are going to use this formula in finding for the capacitance Okay so usually Ginagamit lang to kung yung ating kino-consider na conductor sphere is as Ah yung figure is a sphere Okay where in given yung r and Q now capacitors so what are capacitors as mentioned ko kanina capacitors the difference between

9:44 capacitance and capacitors capacitors are devices while capacitance is the measurement So nakita niyo naman sa definition n capacitance kanina being refer to the ratio of charge gain for potential gain so measurement siya while capacitors are the devices designed for storing charge commonly used in computers or electronic system Okay so yun yung capacitors Yung maliliit na nakikita ninyo pag binuksan ninyo yung radio or yung yung sa cpu or yung sa sa processing yung CPU nung sa computer ' ba May makikita ka doon na parang parang battery na maliliit so yun yung capacitors are devices designed for storing charge so consist two conductor

10:30 plates located with a distance to each other so meron siyang Ah Two plates of course ah They are not tend to touch each other Okay so pwedeng magkaroon ng shock or di kaya of course hindi gagana Okay so when we connect the negatively charged plate with neutral plate excuse the share total charge until the potentials become equal and leaves of the electroscope rises So kung na- recall ninyo before CL sa electrostatic natin meron tayong electroscope for in um pags yung charges nila naka-open siya di ba naka-open siya or nakahiwalay kasi

11:17 nga Ah same the same charges repel ngayon kung magkaiba na yung yung kanilang charges of course they the tendency the yung leaves of the electroscope will come with each other Or will come in contact with each other okay Kasi nga p opposite charges attracts Okay so dito Once na nagbalance na yung charges a magig or maghihiwalay at the electroscope rises so dito may illustration t for that Okay so mamaya then we locate plate a with distance d

12:04 of plate B so the distance between plate A and B is D since we ground the plate it is neutral At The Beginning kasi ' ba yun nga kaya nga di ba yung mga appliances natin may mga ground para neutral siya para pag ginamit natin hindi tayo makukuryente pero Once na ah hindi na effective yung ground or wala ng ground yung appliance so ang tendency Ah pwede tayong ma- electric so since B is negatively charge it affects the plate a and it is positively charged by induction So paano mo pag induction nilalapit mo lang walang contact kasi conduction yun Yung may contact if we put together insulator material between the plates like plastic the leaves of

12:51 electroscope are a little bit closed so ang insulator not good Not conductor of heat ang later so we can conclude that capacitance of the plate depends on the distance between the plates yes so capacitance of the plates depends on the distance between the plates so we have here ito Iyung illustration nung dalawang plate so plate ab distance nila d so let's say positive yung a negative yyung B so nilagyan ng insulator kasi ang tendency ' ba magkakalapit yan ang tendency nila is maglalapit sila Kasi nga they have different ah they have different Uh

13:37 charges eh pero naka-indicate nga Iyung two plates daw should not touch each other Okay hindi sila Dapat mag touch with each other so kasi ma magkaroon ng ilka shock so Iyung positive mo naka-connect sa ground para maging and then meron kang conductor wire So yung wire mo na yan Ito yung ito yung magiging cause ng movement lees Ayan So kung pareho na yung charges lees of course magoopen sila Kasi nga pareho silang negative Pero kung let's say positive kung positive yung charge natin ang

14:25 tendency mag-close yan kasi magiging positive negative Okay in a circuit we represent the capacitor the symbol ito y battery ang ibig sabihin ng symbol na to Actually meron ako dit ipakita Mamaya na complete na list as well as symbols so pag ganito yung nakikita niyong symbol battery that supplies um potential difference An so parang yung source of charge ito y Okay and then ' may mga nakalagay na ayan may BTS so meron tayo ditong complete ah Ba't nawawala siya Sandali

15:14 clasa ay okay nandon pala yung class sa electric current yung nn topic ko nandon pala yung ano yung mga illustrations nung mas kumpleto kasi dito naman ang Focus lang natin is yung charges at saka ung source nung charge or yung battery so ito yung sa battery natin and then ito yung two plates so positive yung isa negative yung isa Okay so ito yung illustration kung magba body diagram tayo so andito yung capacitance para doon sa two plates So yung two plates na yan Ito na yung magiging illustration Okay capacitance of the

15:59 plate depends on the area of the plates distance at saka yung dielectric constant between the plates so ang dielectric constant natin is yung EO Okay so EO and so the capacitance of the plates is found with the following formula so c is equ to EO a / d so a for area so di electric constant and It depends on the type of material so ito for vacuum 88 point 8 85 yan kama Tim 10-1 far per meer tapos pag water ito yun Okay so ito n derive ako ng mga formula so ito yung EO natin or yung constant dielectric dielectric constant Ayan so

16:46 nag-dive ako ng mga formula so pag di hinahanap you're going to use this and then pag area naman hinahanap then you have to use this and then from the capitan Where in we have Q over V Pwede rin tayong mag-dive ng Q which is equal now to cv ang v naman natin is Q over C so yan yung mga list of formula that we are going to use [Musika] [Musika]

17:36 Okay so we have ng [Musika] examples so Calculate the capacitance of the capacitor having dimensions 30 CM by 40 cm and separated with the distance d 8 MM [Musika]

18:25 [Musika] Okay so we have here the given when you say dimensions you're referring it to the length and the ah length and width kung meron kang rectangular object Okay so 30 CM by 40 cm and then yung D natin ay 8 mm and then ang EO or yung dielectric constant natin is 8.5 8.85 10 - 12 c

19:11 m so solution natin equ e o times area div V so bas from the given data nak meters unit natin magconvert m so yung point Ah yung 30 CM div 100 100 cm for 1 m is 3 M tapos yung 40 div 100 is 4 so 30 di 100 Okay m so 40 100 and then

20:00 3 Tim 4 we have 12 m s so This is the area and then for the diameter we have 8 mm so times 1 m is 1000 mm so that is equivalent to ah 008 Okay so Mayon na tayong common units sa meter so 8.85 * 10 - 12c s over n m s so in this case class kung titingan natin This is not

20:47 ma-cancel na natin yung meter and meter so meter sa meter square sa Denominator and then have another meter squ so ang remaining unit na lang natin ay column square over in yung M pupuntahin sa taas so between C squ at saka n ah ma-convert into ah farad kasi ' ba yung farad natin ah is equivalent to C ah

21:33 over B Okay so may mga kenson yung mga units Nila by the way sa kinan ko kasi class na ano ang unit nito Ay ganito c s over n squared d sa kinan ko sa book pero naka-indicate din kanina na This is Pwede rin siang i-f susundin na lang natin yung simplification na per kasi tayo kan naung Gamitin natin kcel mo ang matitira na lang is kaya lang may meters ka pa so

22:27 natin balik kasi natin doon sa mga ibang ano ang Newton is kilogram meters makikita natin yung connection na pag kinancel natin pag ito na lang naiwang units ah then you have farad Ayun kasi ' ba ang newo natin is K seconds [Musika] maka-inom natin then we have 8.85 Tim 10 -

23:14 12 Tim 12 equ 00 1.325 75 10-1 so dito we are asked to [Musika] find for the amount of charge stored on either plate of a capacitor um four times

23:59 10 - 6f when connected across a 12 volt battery so Q ang hinahanap dito so given yung C 4 * 10 -6 farad tapos yung B na 12 volt So kung ang formula natin for Q kanina na na derive natin ay c * b so 4 * 10 - 6c s / 12 new me per C so cancel cancel mo yung Newton and new [Musika] Newton meter and then another Newton meter

24:53 tapos yung ano pa Ayun y si and then yung another CD so the remaining unit is c for charge or if you want class ba usually dahil nakao sila naka scientific notation and pwede natin to i-change to Ilan Ilan yan Tim 10 rais to ne 1 2 3 4 5 so - 5 and

25:43 then kasi pag medyo malalaki na or madami ng decimals so advisable ni na mag ah n ah gumamit ng scientific notation so for bigger and decimal values you are advised to use scientific notation form of numbers or so Ayan direct substitution lang L then we have another one

26:56 s the blet if the plate separation for a capacitor is 2.0 * 10-3 m so determine the area of the plate if the capacitance is exactly 1f So yung D natin is equ to 2.0 10-3 tapos yung C natin is 1 farad ang magiging formula ng area base from our derivation is ito so sa formula yung e yung EO or

27:43 yung constant natin ay nasa Denominator na and then we have 1 f for C 2.0 from for the distance between the two pls so check lang natin tama yung computation so 2 -3 * 1 yun pa rin yun div 8.85 -12 so ang answer is 2.25 9 88 7.6 So kung 22 Ito kasi yung answer inr off na lang

28:35 225 259 88 7006 So kung i- off natin or change natin sa scientific notation 1 2 3 4 5 6 7 8 so kaya time 10 to pos 8 and then yung 2 point magiging 2.29 so magiging 2.26 ito iung kina answer natin or if you want you can use this value Okay so this Same lang naman okay we have another

29:23 example so Calculate the voltage of a battery connected to a parallel plate so we are asked to find for the voltage ah with plate capacitor with a plate area of 2 2.0 CM s and a plate separation of 2 mm So yun yyung distance if the charge stored on the on the plates is 4.0 Pico pic colum so sa area natin naka-indicate na 2.0 CM s ba dapat gagawin nating meter s so in 1 m meron tayong 100 cm since

30:10 naka-indicate yung square So yung 100 is square natin Magiging 10,000 so that is why ang conversion factor natin ay 1 m s is to 10,000 CM s Okay so ito ung multiply natin dito kasi kung mag 1 / 100 lang tayo CM lang yun hindi sila parehong square kaya tayo nag Uh 100 ra to 2 para yung 100 cm magiging CM s Okay ^ 2 so 2 / 10,000 002

30:55 ah m s an Okay and then for 2 mm Same to kanina pag millimeters i-divide lang natin sa 1,000 para makuha natin yung value in meters so 2 / 1000 is 002 so again Bakit tayo nag-divorce and then yung 4 PC or pic column is times 10-12 kasi yung micro kung naalala ninyo times 10-3 Ah -6 so P PC or pic column

31:43 Tim 10-2 so Ayan na so based from this given makukuha na natin yung amas kasi ang formula ng Q is equal to ah Ano ang formula na Ano ba hinahanap dito voltage so formula ng voltage from our Preview from the list of formula ang voltage natin is q / c so that is why kailangan natin munang i-solve yyung C kasi hindi naman given ah no Ang hindi given ay yung kasi ang given doon is yung q or yung charge so h sinad muna natin yung

32:30 q Ah yung q sorry yung capacitance so ito na so for capacitance and we have this one 8.85 Tim 002 div 002 so 8.85 * 10-50 ah -13 May C na tayo so

33:17 i-ssc ang Q natin is ito yung 4 * 10-c and then we have 8.85 * 10 13 farad then ang v na natin is equal to 4.5 ah vols [Musika] so next is a parallel plate

34:04 capacitor is constructed of metal plates so each with an area of 22 m s the capacitance is 7.9 mf nanofarad determine the plate separation distance so ang a natin equ square and then yung C natin ay 7.9 nanofarad Okay um so hinahanap is the distance so ang d natin from the list of formula we have EO a / c Double check

34:50 natin So distance ayan so we have now 8.85 Tim 10 -1 so times 2 m s hindi na tayo nag-convert kasi nga naka meter square na siya div by 7.9 * 10-9 kasi nga naka nano So kung icompute na natin then we have 8.85 * 10 8.85 - 12 Tim 2 /

35:35 7.9 -9 0022 so ito yung value and then ginawan ni lang na 00 0 2 2 4 Ayan So kung imo-modelo 2 3 4 kaya 4 maging 2.24 or 2.2 kung gagawin nating 2.24 Ayan okay lang din Okay so ito yung exact answer kaya lang chinange natin to um scientific notation okay

36:21 now wel proceed to capacitor in series and parallel okay so systems including capacitors more than one has equivalent capacitance so pag yung single capacitors lang yung nandoon or yung single pair of plate lang ang nandoon ito yung mga ah formula natin okay Kaya lang kung madami that then we have another way of finding the total capacitance So capacitors can be connected to each other in two ways So it can be connected in series and in parallel so for parallel ito yung illustration natin Ayan andito yung golds or yung source of

37:09 golds andito yung plates na naka-park capacitors in parallel Okay so This is yung point a mo magfo-four ung charge hanggang point B so makukuha natin yung capacitors kasi given naman So kung meron tayong three different capacitors or Mayon tayong meron tayong q1 and then of course meron din tayong ah capacitance 1 meron tayong charge 1 or q2 capacitance 2 so q3 and then capacitance 3 hindi mo pwedeng i-mix

37:54 hindi pwede na yung charge n one indicate mo doon para sa capacitance nung pang-third ah plate Okay so kailangan yung first plate q1 C1 ang pwede nating kunin second plate ats pwedeng q2 at saka capacitance 2 third plate so Pang third din fourth and so forth so again for parallel ito Iyung illustration So from point a meron kang positive ah charges sa plate tapos sa point B papuntang point B meron kang negative charges naman doon sa plates and then ito yung magiging formula so

38:41 because left hand sides of the capacitors are connected to potential a and right hand naman ay connected sa potential B In other words we can say that each capacitor has the same potential difference so the same yung potential difference daw so so we find the charge of each capacitors as q1 is C1 * V q2 is C2 * B q3 is C3 * B kasi iisa lang yung ah potential difference so total charge of the system is found by adding each charge so para makuha mo Iyung total charge ia-add mo lang lahat nung q1 q2 and q3 okay

39:28 which is that is now equal to equivalent capacitance of the system so para makuha mo yung equivalence capacitance of the system i-add mo lang din yung C1 C2 + C3 ay Ito okay for capacitance in for capacitors in series ito yung

40:14 illustration So from a hanggang B or yung sa potential ng a Ayan so series kasi sunod-sunod Okay and then of course ito pa rin yung D mo and then Para sa formula we have this one so ito naka-indicate in capacitor in series each capacitor has the same charge flow from battery so in this circuit Q charge flows from the positive part of the battery to the left of the capacitor of the first capacitor and it attracts negative charge on the right leg with yung idea So yung negative q charge mo

41:00 nagfo-focus are also charged with the same way so to sum up the the we can say that each capacitor has the same charge with battery Okay so ang Q natin ay C1 v1 q2 natin C2 V2 tapos ang Q natin is C3 v3 para sa volts so we have volt 1 plus volt 2 plus volt 3 and then yung q natin is equal to

41:51 um cq or the equivalent capacitance times V yung CE Q is the um equivalence capacity capacitance or yung parang total na na ah capacitance cq is equivalence capacitance or yung total na capacitance a cq so equivalent capacitance is cq so yung formula class na gagamitin Ay di ba kanina para sa parallel ang cq natin or yung equivalence capacitance ay C1 + C2 + C3 so capacitance ng first pair of plate

42:38 capacitance ng second pair of plate plus capacitance of the third so and so forth pero pag series ayan naka over siya so we have now Q over ceq Q / C1 + Q / c2 Q / C3 or Q tapos 1 / C1 + 1 / C2 + 1 / C3 So kung bakit pakor out to kasi ' ba common naman yung q sa bawat isa soor out Okay so to solve for Uh cq or the common equivalence capacitance you're going to use this So you can use this one or this one

43:31 Ah ito inano ko lang naalala ko kinut ko lang para mas malinaw ay so equivalent capacitance becomes 1 / cq + 1 / C1 + 1 / C2 + 1 / cq So this will be the Um yung final na formula that we are going to use So makikita ninyo dito sa mga computations m so calculate equivalence capacitance between points a at saka yung point B so sa first

44:17 capacitance natin or sa first ah plate a pair of plate we have C1 which is equivalent to 2c So ibig sabihin wala pa tayong eksaktong value pero ininda lang or i-express yung capacitance in terms of c so sa C1 natin meron tayong 2c tapos sa C sub2 natin or para doon sa second plate natin ay meron tayong C tapos sa third pair of plate ay ah we have C nakalagay sa problem so ito yung solution so ang first yung c and one are in parallel ' ba kung titingnan natin yung C1 natin at

45:02 saka yung C2 parallel with each other tapos kung ano yung result nung C1 and C2 naman natin ay naka-set naman siya dito sa season 3 So yan ang tandaan ninyo CL ah pwedeng halo-halo yung ah connection nung nung mga capacitors natin in a given problem so Again in this case yung C1 at saka yung c2 two are parallel with each other tapos yung result natin dito is series with C3 Okay so dito since C1 and C2 are in parallel TH the equivalence of them is magiging C1 2 pinagsama natin kasi Iyung capacity sa 1 and 2 so we have now the formula C1 + C sub2

45:52 so sa given ang C1 natin ay 2c tapos c2 natin is c kaya all in all ang c12 natin ay 3c okay tapos itong c12 natin AT T saka yung C3 are in series kaya ang magiging equivalence natin nung capacitance ay ito kasi based do sa formula na pag naka-oo over c12 1 / C3 So yung yung c12 natin ang value niya na ngayon ay 3c plus 1 over

46:39 value ng C3 is c tapos ah Dahil fraction plus fraction i-recall natin yung ah tamang the proper way of adding fractions so ang common ano natin dito L CD natin is 3c Okay so 3c ' ba ang rule is LCD divided by the first Denominator times the numerator tapos divide sa second tapos times the numerator Okay so again ang LCD natin for 3 CNC I 3c so 3c / 3c 1 1 * 1 is 1 kay 1o 3c / C so

47:27 3 * 1 Then we have 3 So ang LCD natin is 3c ang numerator natin ay 1 + 3 So that is now equal to 4 / 3c so ang hinahanap natin CL e cq so meron na tayong 1 / cq e 4 / 3c so para ma-solve natin to apply natin yung ratio and proportion or magc-cr multiply tayo so 1 ah cq Tim 4 dito na tayo so cq * 4 then you have 4 cq 1 3c Then you have 3c so lagyan

48:15 natin So nag-cross multiply tayo kaya siya naging 4 and then cross multiply din tayo then you have now so ito yung result and then Incas na pinag cross multiply natin So ang hinahanap natin ay may ceq so divide both sides by 4 so 4 ceq divided 4 equ cq 3c / 4 then you

49:01 have 3c / 4 Okay So ibig sabihin ang value ng cq natin is 3c / 4 so say for example pag nilagyan natin ito ha let's say yung value ng c natin So c capacitance is equal to let's say 2 farad Ayan then we can say that sa next page na lang tayo

49:58 then we can say that the equivalence or cq is now equal to kung 34 siya that is equal now to so 3 times yung capac yung capacitance na example ay 2f divide mo sa 4 then we have

50:45 Ilan 6 / 4 so 1.5 so 6 / 4 is 1 5 example lang ha so say for example yung capacitance natin or yung value ng c for the capacitance kanina is 2f then you have 3 times the capacitance which is 2f div 4 is 1.5 so ito yung magiging total or overall capacitance of our parallel and series capacitors second example So yung C daw or C saban natin

51:33 is 10f and c sub2 is 5f so determine the effective capacitance for C1 and C2 connected in series and in parallel so dalawa yung sasagutan natin dito yung C1 daw at saka yyung C2 connected sila pareho in series tapos in parallel so we have two different Uh connections So if we're going to use series ito yung magiging formula natin So we have one over se

52:19 cq so 1 / ceq equ 1 over C1 + 1 / c sub2 So yung capacitance natin for C1 and C2 na naka series ay 1 / 10+ 1/5 is now equ to 1 + 2 kasi nga ang lowest um LCD natin dito is 10 so 10 / 10 is 1 10 / 5 is 2 * 1 is 2 so we have na 1 + 2 3 over 10 so nag-cross

53:06 tayo so Pag nag-cross tayo again yung three times effect an magiging equ 10 tapos divide both sides by 3 kaya magiging cq na lang or equ to 10 di 3 So 10 di 3 3.3 parel 4 parallel naman then we have if you want classe mo gamitin yung

53:52 c12 C1 c2 to 10 + 5 kasi nga parallel siya So wala na tayong fraction so cq is equ to 15 So kung titingnan natin class mas mataas yung value sa parallel compared to series last problem and then I'm going to give

54:38 you exercises na lang okay for our last problem so we have this one in the circuit given below yung C one natin ay ito yon 60 microfarad C sub two is 20 microfarad tapos C sub 3 is 9 microfarad and then

55:23 C4 is 12 microfarad So if the potential difference between points A and B or yung vac is 120 volt so between A and B okay Meron siyang potential difference na vac so find the charge of the second capacitor so second capacitor natin of course is ito so we have to find for the charge So take note CL yung C1 and C2 natin ay series tapos yung C2 and C3 natin ay naka parallel tapos yung result nitong C2 and 3 naman natin ay

56:09 naka-4 so combination yung C and 1 naka yung result ng C1 and 2 natin ay naka parallel sa C3 and then yung result nung c12 natin at saka yung C3 ay naka series sa c 4 so step by step natin isa-isahin natin Ayan yung mga given so since pare-pareho lang naman yung given Gamitin na lang natin yung microfarad Okay so yung first so C1 and C2 are series to form c12 Okay para hindi tayo malito mamaya so 1 / c12 equ 1 / C1 + 1 / C2 which is equ to 1 / 60

56:57 microfarad + 1 over ang C sub2 natin is 20 LCD ng dalawa 60 and 20 of course 60 so 60 / 60 is 1 times sa numerator na 1 1 pa rin yan plus next yung 60 i-divide doon sa second Denominator na 20 so 60 / 20 is 3 * 1 we have 3 So 1 + 4 ah 1 + 3 sa numerator then we have 4 copy lang yung Denominator Okay next is ah Kukunin na natin yung um exact value ng c12 so hindi muna natin gamitin yung C equivalence kasi nga nasa 1 and 2 pa

57:45 lang tayo Tapos marami pa tayong karugtong na mga series at saka so cross multiply So you have 4 * c12 so we have now 4 C1 2 1 * 60 equ 60 so divide both sides by 4 so 4 c12 / 4 c12 na lang 60 / 4 so we have 15 so para sa c12 ah na parallel connection meron tayong Ay sorry na series connection meron tayong 15 microfarad so again yung C1 po natin ay a series Okay so Kukunin na natin ngayon dahil meron na tayong C1

58:31 and 2 kunin na natin yung um capacitance dito sa dalawang parallel na yan So yung c12 and C3 are parallel so gagamitin na lang natin yung um symbol na C1 2 3 Okay so C1 2 parallel with C3 so we have this one so dahil parallel siya wala na tayong fraction so c12 3 is now equal to c12 plus yung C3 so ang c12 natin na na-solve kanina is 15 plus yung C3 na 9 then we have 24 microfarad so ang exact value na natin para doon sa

59:19 ah C1 2 3 or ung sa parallel natin ay 24 next yung c123 naman natin ' ba parallel siya doon sa C sa C4 So yung buong ito result nito ay ay sorry Siri ah series with C4 naka sa C4 so ang magiging result natin ay equivalence Uh capacitance so 1 / cq is equ to 1 / c123

1:00:06 plus yung pangapat na 1 / C4 So yung result ng 123 natin ay 24 kaya we have now 1 / 24 plus 1 / C4 so 1 / 12 and then we have 24 as the LCD so 24 / 24 is is 1 24 / 12 is 2 * 1 Then we have 2 so 1 + 2 is 3 / 24 Okay class baka mayung iba nag-iisip na Bakit hindi bakit hindi ncis cross Multiplication ay hindi nag nag-cross Multiplication Actually pwede siyang magcross Multiplication kung gusto niyo Pero kailangan naka lowest term yung answers niyo ha So walang problema d Pwede kayong mag ah at saka

1:00:53 kahit naman hindi kayo maglo lowest term Pagdating naman dito iss simplify niyo Same lang din yung formula Sige mamaya i-try natin So 3 / 24 So you have na 1 / cq is equ 3 / 24 cross multiplied then we have 3 cq 1 * 24 is 24 so divide both sides by 3 So 3ce EQ / 3 we have cq 24 / 3/2 B so ito yung value ng ating cq So kung gusto niyong i-try yung mag-cross multiply pwede

1:01:38 naman and then this na lang natin hirap So kung mag-cross multiply tayo 1 ah 1 Tim 12 1 * 12 is 12 plus 1 Tim 1 * 24 is 24 tapos This

1:02:24 is 2 4 * 12 kasi pag nagco-computer and then we have now is equ

1:03:15 to nag-cross multiply tayo magiging 36 36 c is equ to 288 So ngayon 288 / 36 sagot mo is 8 the so c [Musika] so wala namang changes sa sagot the same

1:04:01 lang sila [Musika] ilag Ayan ang gagamitin niyo Nag cross Multiplication kulp denominators mly the same [Musika] din for going to cross MPC pareho nito or um kukunin mo yung LCD tapos idivide mo lang yung LCD do sa first Denominator multiply sa numerator tapos LCD div second Denominator times the numerator next We're not yet

1:04:46 done kasi ang tinatanong is yung charge do second now ang total charge of the systems from a to C is equ to Q equ cv Okay tapos yung cv natin kasi ang sabi naman from a to C So ibig sabihin ung C natin dito is ung ah equal din siya So ung C natin na tukoy dito is equal din sa capac ah equivalence capacitance times yung

1:05:33 ah charges from a to C which is 120 ay yyung volts natin or yung potential difference from a to C which is 120 so 8 * 120 ang answer natin is 96 16 micr So this is the total charge from a to C okay ngayon ang potential difference naman between b and C so between b and C meron tayong um Q over C4 kasi between and C ang dulo

1:06:21 natin dito is of course yung C4 ito yung nasa c Okay mula sa B puntang C so ang invol of course is capacitance 4 Okay so balikan natin So potential difference between b and c is v b at vc so that is equal now to charge div by C4 so ' ba naka-indicate naman dito na ang yung q natin or yung total charge ay applicable sa buong system from a to C So kung kukunin lang natin yung sa C sa B and C then we have this one so Q 960 pa rin kasi Ian

1:07:09 overall over C4 na given Iyung 12 microfarad kanina so we have now that is equal 960 div so 80 volt So yung nasa V bc is equ 80 vol So ngayon ang kukunin natin naman ay yung potential difference between A and B So kung kukunin natin yung potential difference mula a hanggang b lang i-consider natin yung vab

1:07:57 so we have now vad is equ to ah vac - vbc equ 120 vol - 80 kasi di ba ang kabuuan natin is 120 so nakuha natin yung sa part ng b and C lang para makuha mo yung another part ima minus mo lang yung total at saka yung isang part so the remaining part which is 40 volts is the potential difference from or between A and B Okay next so ang qa natin since at saka yung B So yung a natin

1:08:44 ito So yung charges sa a at saka B are equal since equal then can say that yung CB times vab kasi We're Looking for the second ' ba sabi yung second charge so yung first kasi natin is a So um yung second natin is B so that is why we are using CB times bab is equal now to yung sa 1 and two Ayan So kung bakit

1:09:30 ginamit natin yan So pwede ko ditong i- indicate that is also r c So bakit Yan ang ginamit Kasi yan yung capacitance between sa a at saka sa B so qa or charges sa a at saka sa B natin is equal to c12 or consider na natin as CB and then bab then we have 15 Tim 40 volts that is now equivalent to 600 micr

1:10:16 so 15 * 4 tama 60 600 micro So ibig sabihin Ito yung answer doon sa question k What is the charge in the second capacitor ayan kasi ito yung first capacitor mo ito yung second capacitor okay So that's all for today and then

1:11:02 ah magpo-post na lang ako ng exercises sa EDM Okay so God bless everyone Bye for